141310312310441 has 4 divisors (see below), whose sum is σ = 141310354192512. Its totient is φ = 141310270428372.

The previous prime is 141310312310413. The next prime is 141310312310581. The reversal of 141310312310441 is 144013213013141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141310312310441 is a prime.

It is a super-2 number, since 2×141310312310441² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141310312312441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15389441 + ... + 22791566.

It is an arithmetic number, because the mean of its divisors is an integer number (35327588548128).

Almost surely, 2^{141310312310441} is an apocalyptic number.

It is an amenable number.

141310312310441 is a deficient number, since it is larger than the sum of its proper divisors (41882071).

141310312310441 is an equidigital number, since it uses as much as digits as its factorization.

141310312310441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41882070.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 141310312310441 its reverse (144013213013141), we get a palindrome (285323525323582).

The spelling of 141310312310441 in words is "one hundred forty-one trillion, three hundred ten billion, three hundred twelve million, three hundred ten thousand, four hundred forty-one".