1413111403 has 4 divisors (see below), whose sum is σ = 1541576088. Its totient is φ = 1284646720.

The previous prime is 1413111397. The next prime is 1413111407. The reversal of 1413111403 is 3041113141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3041113141 = 11 ⋅276464831.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1413111403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1413111407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64232326 + ... + 64232347.

It is an arithmetic number, because the mean of its divisors is an integer number (385394022).

Almost surely, 2^1413111403 is an apocalyptic number.

1413111403 is a deficient number, since it is larger than the sum of its proper divisors (128464685).

1413111403 is a wasteful number, since it uses less digits than its factorization.

1413111403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128464684.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1413111403 is about 37591.3740504388. The cubic root of 1413111403 is about 1122.1703777009.

Adding to 1413111403 its reverse (3041113141), we get a palindrome (4454224544).

The spelling of 1413111403 in words is "one billion, four hundred thirteen million, one hundred eleven thousand, four hundred three".