14131222411321 has 4 divisors (see below), whose sum is σ = 14153199429712. Its totient is φ = 14109245392932.

The previous prime is 14131222411309. The next prime is 14131222411343. The reversal of 14131222411321 is 12311422213141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14131222411321 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14131222411321.

It is not an unprimeable number, because it can be changed into a prime (14131222411301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10988508231 + ... + 10988509516.

It is an arithmetic number, because the mean of its divisors is an integer number (3538299857428).

Almost surely, 2^{14131222411321} is an apocalyptic number.

It is an amenable number.

14131222411321 is a deficient number, since it is larger than the sum of its proper divisors (21977018391).

14131222411321 is an equidigital number, since it uses as much as digits as its factorization.

14131222411321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21977018390.

The product of its digits is 2304, while the sum is 28.

Adding to 14131222411321 its reverse (12311422213141), we get a palindrome (26442644624462).

The spelling of 14131222411321 in words is "fourteen trillion, one hundred thirty-one billion, two hundred twenty-two million, four hundred eleven thousand, three hundred twenty-one".