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14131253103353 = 2113311021198173
BaseRepresentation
bin1100110110100011000001…
…0100100100101011111001
31212000221020022210110000122
43031220300110210223321
53323011301243301403
650015450312343025
72655643424334341
oct315506024445371
955027208713018
1014131253103353
114559037a80921
1217028940a4a75
137b6757623a49
1436bd5612bd21
151978bdc8b838
hexcda30524af9

14131253103353 has 16 divisors (see below), whose sum is σ = 14255140949952. Its totient is φ = 14007985992000.

The previous prime is 14131253103337. The next prime is 14131253103379. The reversal of 14131253103353 is 35330135213141.

It is a cyclic number.

It is not a de Polignac number, because 14131253103353 - 24 = 14131253103337 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14131253103323) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71208575 + ... + 71406747.

It is an arithmetic number, because the mean of its divisors is an integer number (890946309372).

Almost surely, 214131253103353 is an apocalyptic number.

It is an amenable number.

14131253103353 is a deficient number, since it is larger than the sum of its proper divisors (123887846599).

14131253103353 is a wasteful number, since it uses less digits than its factorization.

14131253103353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 199736.

The product of its (nonzero) digits is 48600, while the sum is 35.

Adding to 14131253103353 its reverse (35330135213141), we get a palindrome (49461388316494).

The spelling of 14131253103353 in words is "fourteen trillion, one hundred thirty-one billion, two hundred fifty-three million, one hundred three thousand, three hundred fifty-three".

Divisors: 1 211 331 1021 69841 198173 215431 337951 41814503 65595263 71307661 202334633 13840600493 42692607563 66972763523 14131253103353