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1413144124251 = 3471048041417
BaseRepresentation
bin10100100100000101111…
…101000001101101011011
312000002120102222111020120
4110210011331001231123
5141123104343434001
63001104530524323
7204045012603006
oct24440575015533
95002512874216
101413144124251
114a53470213a2
121a9a631366a3
13a3349acb1a2
144c57a17053d
1526b5c080236
hex14905f41b5b

1413144124251 has 4 divisors (see below), whose sum is σ = 1884192165672. Its totient is φ = 942096082832.

The previous prime is 1413144124187. The next prime is 1413144124289. The reversal of 1413144124251 is 1524214413141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413144124251 - 26 = 1413144124187 is a prime.

It is a super-2 number, since 2×14131441242512 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1413144174251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235524020706 + ... + 235524020711.

It is an arithmetic number, because the mean of its divisors is an integer number (471048041418).

Almost surely, 21413144124251 is an apocalyptic number.

1413144124251 is a deficient number, since it is larger than the sum of its proper divisors (471048041421).

1413144124251 is an equidigital number, since it uses as much as digits as its factorization.

1413144124251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 471048041420.

The product of its digits is 15360, while the sum is 33.

Adding to 1413144124251 its reverse (1524214413141), we get a palindrome (2937358537392).

The spelling of 1413144124251 in words is "one trillion, four hundred thirteen billion, one hundred forty-four million, one hundred twenty-four thousand, two hundred fifty-one".

Divisors: 1 3 471048041417 1413144124251