Search a number
-
+
14132040033 = 34710680011
BaseRepresentation
bin11010010100101010…
…11101000101100001
31100110212221000110010
431022111131011201
5212420300240113
610254150355133
71010130233616
oct151225350541
940425830403
1014132040033
115aa2193931
1228a495baa9
131442a90087
14980c4850d
1557aa161c3
hex34a55d161

14132040033 has 4 divisors (see below), whose sum is σ = 18842720048. Its totient is φ = 9421360020.

The previous prime is 14132039969. The next prime is 14132040047. The reversal of 14132040033 is 33004023141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14132040033 - 26 = 14132039969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14132039991 and 14132040009.

It is not an unprimeable number, because it can be changed into a prime (14132000033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355340003 + ... + 2355340008.

It is an arithmetic number, because the mean of its divisors is an integer number (4710680012).

Almost surely, 214132040033 is an apocalyptic number.

It is an amenable number.

14132040033 is a deficient number, since it is larger than the sum of its proper divisors (4710680015).

14132040033 is an equidigital number, since it uses as much as digits as its factorization.

14132040033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4710680014.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 14132040033 its reverse (33004023141), we get a palindrome (47136063174).

The spelling of 14132040033 in words is "fourteen billion, one hundred thirty-two million, forty thousand, thirty-three".

Divisors: 1 3 4710680011 14132040033