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14132162555 = 57403776073
BaseRepresentation
bin11010010100101011…
…11010111111111011
31100110220011020111222
431022111322333323
5212420313200210
610254153142255
71010131254050
oct151225727773
940426136458
1014132162555
115aa2267995
1228a49ba98b
131442b03a84
14980c7b027
1557aa3c655
hex34a57affb

14132162555 has 8 divisors (see below), whose sum is σ = 19381251552. Its totient is φ = 9690625728.

The previous prime is 14132162537. The next prime is 14132162563. The reversal of 14132162555 is 55526123141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14132162555 - 210 = 14132161531 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (35), and also a Moran number because the ratio is a prime number: 403776073 = 14132162555 / (1 + 4 + 1 + 3 + 2 + 1 + 6 + 2 + 5 + 5 + 5).

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 201888002 + ... + 201888071.

It is an arithmetic number, because the mean of its divisors is an integer number (2422656444).

Almost surely, 214132162555 is an apocalyptic number.

14132162555 is a deficient number, since it is larger than the sum of its proper divisors (5249088997).

14132162555 is an equidigital number, since it uses as much as digits as its factorization.

14132162555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 403776085.

The product of its digits is 36000, while the sum is 35.

Adding to 14132162555 its reverse (55526123141), we get a palindrome (69658285696).

The spelling of 14132162555 in words is "fourteen billion, one hundred thirty-two million, one hundred sixty-two thousand, five hundred fifty-five".

Divisors: 1 5 7 35 403776073 2018880365 2826432511 14132162555