Base | Representation |
---|---|
bin | 10100100100001011010… |
… | …000011101000010100011 |
3 | 12000002210122102002011012 |
4 | 110210023100131002203 |
5 | 141123300133244021 |
6 | 3001121430011135 |
7 | 204050143113212 |
oct | 24441320350243 |
9 | 5002718362135 |
10 | 1413233103011 |
11 | 4a5392275464 |
12 | 1a9a88aa6aab |
13 | a3362383342 |
14 | 4c587cd3079 |
15 | 26b64ca935b |
hex | 1490b41d0a3 |
1413233103011 has 4 divisors (see below), whose sum is σ = 1413249334224. Its totient is φ = 1413216871800.
The previous prime is 1413233102977. The next prime is 1413233103013. The reversal of 1413233103011 is 1103013323141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1413233103011 - 226 = 1413165994147 is a prime.
It is a super-2 number, since 2×14132331030112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1413233103013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7984295 + ... + 8159376.
It is an arithmetic number, because the mean of its divisors is an integer number (353312333556).
Almost surely, 21413233103011 is an apocalyptic number.
1413233103011 is a deficient number, since it is larger than the sum of its proper divisors (16231213).
1413233103011 is an equidigital number, since it uses as much as digits as its factorization.
1413233103011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16231212.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1413233103011 its reverse (1103013323141), we get a palindrome (2516246426152).
The spelling of 1413233103011 in words is "one trillion, four hundred thirteen billion, two hundred thirty-three million, one hundred three thousand, eleven".
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