Base | Representation |
---|---|
bin | 100000001000100001101011… |
… | …101111000011010101010001 |
3 | 200112101101102112021112202120 |
4 | 200020201223233003111101 |
5 | 122010420321304412423 |
6 | 1220323025014204453 |
7 | 41524164610440111 |
oct | 4010415357032521 |
9 | 615341375245676 |
10 | 141323411404113 |
11 | 41036a164978a4 |
12 | 13a25510653729 |
13 | 60b1981b9c283 |
14 | 26c8137c57041 |
15 | 115122d8d8ee3 |
hex | 80886bbc3551 |
141323411404113 has 16 divisors (see below), whose sum is σ = 201600264763200. Its totient is φ = 87793663682880.
The previous prime is 141323411404099. The next prime is 141323411404213. The reversal of 141323411404113 is 311404114323141.
It is not a de Polignac number, because 141323411404113 - 217 = 141323411273041 is a prime.
It is a super-2 number, since 2×1413234114041132 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (141323411404213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20322603858 + ... + 20322610811.
It is an arithmetic number, because the mean of its divisors is an integer number (12600016547700).
Almost surely, 2141323411404113 is an apocalyptic number.
It is an amenable number.
141323411404113 is a deficient number, since it is larger than the sum of its proper divisors (60276853359087).
141323411404113 is a wasteful number, since it uses less digits than its factorization.
141323411404113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40645214752.
The product of its (nonzero) digits is 13824, while the sum is 33.
Adding to 141323411404113 its reverse (311404114323141), we get a palindrome (452727525727254).
The spelling of 141323411404113 in words is "one hundred forty-one trillion, three hundred twenty-three billion, four hundred eleven million, four hundred four thousand, one hundred thirteen".
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