14132445211331 has 4 divisors (see below), whose sum is σ = 14132920137600. Its totient is φ = 14131970285064.

The previous prime is 14132445211303. The next prime is 14132445211337. The reversal of 14132445211331 is 13311254423141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14132445211331 - 2³⁸ = 13857567304387 is a prime.

It is a super-2 number, since 2×14132445211331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14132445211291 and 14132445211300.

It is not an unprimeable number, because it can be changed into a prime (14132445211337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 237418496 + ... + 237478013.

It is an arithmetic number, because the mean of its divisors is an integer number (3533230034400).

Almost surely, 2^{14132445211331} is an apocalyptic number.

14132445211331 is a deficient number, since it is larger than the sum of its proper divisors (474926269).

14132445211331 is an equidigital number, since it uses as much as digits as its factorization.

14132445211331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 474926268.

The product of its digits is 34560, while the sum is 35.

Adding to 14132445211331 its reverse (13311254423141), we get a palindrome (27443699634472).

The spelling of 14132445211331 in words is "fourteen trillion, one hundred thirty-two billion, four hundred forty-five million, two hundred eleven thousand, three hundred thirty-one".