141330113 has 4 divisors (see below), whose sum is σ = 148768560. Its totient is φ = 133891668.

The previous prime is 141330103. The next prime is 141330143. The reversal of 141330113 is 311033141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311033141 = 4523 ⋅68767.

It is a cyclic number.

It is not a de Polignac number, because 141330113 - 2¹⁴ = 141313729 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 141330091 and 141330100.

It is not an unprimeable number, because it can be changed into a prime (141330103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3719195 + ... + 3719232.

It is an arithmetic number, because the mean of its divisors is an integer number (37192140).

Almost surely, 2^141330113 is an apocalyptic number.

It is an amenable number.

141330113 is a deficient number, since it is larger than the sum of its proper divisors (7438447).

141330113 is an equidigital number, since it uses as much as digits as its factorization.

141330113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7438446.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 141330113 is about 11888.2342254853. The cubic root of 141330113 is about 520.8886591994. Note that the first 3 decimals are identical.

Adding to 141330113 its reverse (311033141), we get a palindrome (452363254).

The spelling of 141330113 in words is "one hundred forty-one million, three hundred thirty thousand, one hundred thirteen".