1413304011433 has 4 divisors (see below), whose sum is σ = 1415206171008. Its totient is φ = 1411401851860.

The previous prime is 1413304011409. The next prime is 1413304011437. The reversal of 1413304011433 is 3341104033141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1413304011433 - 2³³ = 1404714076841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1413304011437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 951078673 + ... + 951080158.

It is an arithmetic number, because the mean of its divisors is an integer number (353801542752).

Almost surely, 2^{1413304011433} is an apocalyptic number.

It is an amenable number.

1413304011433 is a deficient number, since it is larger than the sum of its proper divisors (1902159575).

1413304011433 is an equidigital number, since it uses as much as digits as its factorization.

1413304011433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1902159574.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1413304011433 its reverse (3341104033141), we get a palindrome (4754408044574).

The spelling of 1413304011433 in words is "one trillion, four hundred thirteen billion, three hundred four million, eleven thousand, four hundred thirty-three".