14133212441 has 4 divisors (see below), whose sum is σ = 14152032384. Its totient is φ = 14114392500.

The previous prime is 14133212411. The next prime is 14133212461. The reversal of 14133212441 is 14421233141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14421233141 = 7 ⋅2060176163.

It is a cyclic number.

It is not a de Polignac number, because 14133212441 - 2¹⁸ = 14132950297 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14133212441.

It is not an unprimeable number, because it can be changed into a prime (14133212411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9408845 + ... + 9410346.

It is an arithmetic number, because the mean of its divisors is an integer number (3538008096).

Almost surely, 2^14133212441 is an apocalyptic number.

It is an amenable number.

14133212441 is a deficient number, since it is larger than the sum of its proper divisors (18819943).

14133212441 is an equidigital number, since it uses as much as digits as its factorization.

14133212441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18819942.

The product of its digits is 2304, while the sum is 26.

Adding to 14133212441 its reverse (14421233141), we get a palindrome (28554445582).

The spelling of 14133212441 in words is "fourteen billion, one hundred thirty-three million, two hundred twelve thousand, four hundred forty-one".