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14134012641 = 327224349407
BaseRepresentation
bin11010010100111001…
…11110101011100001
31100111000122020100200
431022130332223201
5212421301401031
610254300535413
71010153060640
oct151234765341
940430566320
1014134012641
115aa3310991
1228a5551569
131443300bb8
149811dd357
1557aca58e6
hex34a73eae1

14134012641 has 12 divisors (see below), whose sum is σ = 23332338432. Its totient is φ = 8076578616.

The previous prime is 14134012597. The next prime is 14134012649. The reversal of 14134012641 is 14621043141.

14134012641 is a `hidden beast` number, since 1 + 4 + 1 + 3 + 4 + 0 + 12 + 641 = 666.

It is not a de Polignac number, because 14134012641 - 27 = 14134012513 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14134012649) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 112174641 + ... + 112174766.

It is an arithmetic number, because the mean of its divisors is an integer number (1944361536).

Almost surely, 214134012641 is an apocalyptic number.

It is an amenable number.

14134012641 is a deficient number, since it is larger than the sum of its proper divisors (9198325791).

14134012641 is a wasteful number, since it uses less digits than its factorization.

14134012641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 224349420 (or 224349417 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 14134012641 its reverse (14621043141), we get a palindrome (28755055782).

The spelling of 14134012641 in words is "fourteen billion, one hundred thirty-four million, twelve thousand, six hundred forty-one".

Divisors: 1 3 7 9 21 63 224349407 673048221 1570445849 2019144663 4711337547 14134012641