141340311401 has 4 divisors (see below), whose sum is σ = 141635385600. Its totient is φ = 141045237204.

The previous prime is 141340311397. The next prime is 141340311407. The reversal of 141340311401 is 104113043141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141340311401 - 2² = 141340311397 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141340311407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147536381 + ... + 147537338.

It is an arithmetic number, because the mean of its divisors is an integer number (35408846400).

Almost surely, 2^141340311401 is an apocalyptic number.

It is an amenable number.

141340311401 is a deficient number, since it is larger than the sum of its proper divisors (295074199).

141340311401 is an equidigital number, since it uses as much as digits as its factorization.

141340311401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 295074198.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 141340311401 its reverse (104113043141), we get a palindrome (245453354542).

The spelling of 141340311401 in words is "one hundred forty-one billion, three hundred forty million, three hundred eleven thousand, four hundred one".