Base | Representation |
---|---|
bin | 100000001000110011010011… |
… | …100111100111010101000011 |
3 | 200112110012021021202211201212 |
4 | 200020303103213213111003 |
5 | 122011223100020412201 |
6 | 1220335434422320335 |
7 | 41525434542242222 |
oct | 4010632347472503 |
9 | 615405237684655 |
10 | 141342334154051 |
11 | 41043a4692aa08 |
12 | 13a291118890ab |
13 | 60b36a9330224 |
14 | 26c9011042cb9 |
15 | 1151989cb4abb |
hex | 808cd39e7543 |
141342334154051 has 4 divisors (see below), whose sum is σ = 146216207745600. Its totient is φ = 136468460562504.
The previous prime is 141342334154017. The next prime is 141342334154059. The reversal of 141342334154051 is 150451433243141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141342334154051 - 218 = 141342333891907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141342334154059) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2436936795731 + ... + 2436936795788.
It is an arithmetic number, because the mean of its divisors is an integer number (36554051936400).
Almost surely, 2141342334154051 is an apocalyptic number.
141342334154051 is a deficient number, since it is larger than the sum of its proper divisors (4873873591549).
141342334154051 is an equidigital number, since it uses as much as digits as its factorization.
141342334154051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4873873591548.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 141342334154051 its reverse (150451433243141), we get a palindrome (291793767397192).
The spelling of 141342334154051 in words is "one hundred forty-one trillion, three hundred forty-two billion, three hundred thirty-four million, one hundred fifty-four thousand, fifty-one".
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