1413433240033 has 4 divisors (see below), whose sum is σ = 1433340750528. Its totient is φ = 1393525729540.

The previous prime is 1413433240031. The next prime is 1413433240061. The reversal of 1413433240033 is 3300423343141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1413433240033 - 2¹ = 1413433240031 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1413433239977 and 1413433240004.

It is not an unprimeable number, because it can be changed into a prime (1413433240031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9953755141 + ... + 9953755282.

It is an arithmetic number, because the mean of its divisors is an integer number (358335187632).

Almost surely, 2^{1413433240033} is an apocalyptic number.

It is an amenable number.

1413433240033 is a deficient number, since it is larger than the sum of its proper divisors (19907510495).

1413433240033 is an equidigital number, since it uses as much as digits as its factorization.

1413433240033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19907510494.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1413433240033 its reverse (3300423343141), we get a palindrome (4713856583174).

The spelling of 1413433240033 in words is "one trillion, four hundred thirteen billion, four hundred thirty-three million, two hundred forty thousand, thirty-three".