Base | Representation |
---|---|
bin | 11010010100111100… |
… | …01111110101001011 |
3 | 1100111001021010022120 |
4 | 31022132033311023 |
5 | 212421343020120 |
6 | 10254312022323 |
7 | 1010155644006 |
oct | 151236176513 |
9 | 40431233276 |
10 | 14134345035 |
11 | 5aa3518698 |
12 | 28a56919a3 |
13 | 14433b9295 |
14 | 98128853d |
15 | 57ad1e140 |
hex | 34a78fd4b |
14134345035 has 8 divisors (see below), whose sum is σ = 22614952080. Its totient is φ = 7538317344.
The previous prime is 14134345013. The next prime is 14134345039. The reversal of 14134345035 is 53054343141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14134345035 - 222 = 14130150731 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14134344987 and 14134345005.
It is not an unprimeable number, because it can be changed into a prime (14134345039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 471144820 + ... + 471144849.
It is an arithmetic number, because the mean of its divisors is an integer number (2826869010).
Almost surely, 214134345035 is an apocalyptic number.
14134345035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14134345035 is a deficient number, since it is larger than the sum of its proper divisors (8480607045).
14134345035 is an equidigital number, since it uses as much as digits as its factorization.
14134345035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 942289677.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 14134345035 its reverse (53054343141), we get a palindrome (67188688176).
The spelling of 14134345035 in words is "fourteen billion, one hundred thirty-four million, three hundred forty-five thousand, thirty-five".
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