Base | Representation |
---|---|
bin | 100000001000110100110110… |
… | …111111010100110011011011 |
3 | 200112110100120110211100021001 |
4 | 200020310312333110303123 |
5 | 122011240003314022021 |
6 | 1220340312055325431 |
7 | 41525524054666666 |
oct | 4010646677246333 |
9 | 615410513740231 |
10 | 141344001314011 |
11 | 41044721a02961 |
12 | 13a294b8080877 |
13 | 60b38b384bc02 |
14 | 26c912c61a6dd |
15 | 1151a3632d091 |
hex | 808d36fd4cdb |
141344001314011 has 4 divisors (see below), whose sum is σ = 141344060116072. Its totient is φ = 141343942511952.
The previous prime is 141344001313927. The next prime is 141344001314141. The reversal of 141344001314011 is 110413100443141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141344001314011 - 27 = 141344001313883 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141344001314611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25634610 + ... + 30656503.
It is an arithmetic number, because the mean of its divisors is an integer number (35336015029018).
Almost surely, 2141344001314011 is an apocalyptic number.
141344001314011 is a deficient number, since it is larger than the sum of its proper divisors (58802061).
141344001314011 is an equidigital number, since it uses as much as digits as its factorization.
141344001314011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58802060.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 141344001314011 its reverse (110413100443141), we get a palindrome (251757101757152).
The spelling of 141344001314011 in words is "one hundred forty-one trillion, three hundred forty-four billion, one million, three hundred fourteen thousand, eleven".
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