14135254111131 has 4 divisors (see below), whose sum is σ = 18847005481512. Its totient is φ = 9423502740752.

The previous prime is 14135254111109. The next prime is 14135254111171. The reversal of 14135254111131 is 13111145253141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14135254111131 - 2¹⁷ = 14135253980059 is a prime.

It is a super-2 number, since 2×14135254111131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14135254111092 and 14135254111101.

It is not an unprimeable number, because it can be changed into a prime (14135254111171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355875685186 + ... + 2355875685191.

It is an arithmetic number, because the mean of its divisors is an integer number (4711751370378).

Almost surely, 2^{14135254111131} is an apocalyptic number.

14135254111131 is a deficient number, since it is larger than the sum of its proper divisors (4711751370381).

14135254111131 is an equidigital number, since it uses as much as digits as its factorization.

14135254111131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4711751370380.

The product of its digits is 7200, while the sum is 33.

Adding to 14135254111131 its reverse (13111145253141), we get a palindrome (27246399364272).

The spelling of 14135254111131 in words is "fourteen trillion, one hundred thirty-five billion, two hundred fifty-four million, one hundred eleven thousand, one hundred thirty-one".