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141353310551353 = 151193549510623
BaseRepresentation
bin100000001000111101100001…
…110111001111110100111001
3200112111020121020210121011021
4200020331201313033310321
5122011413040000120403
61220344451524502441
741526303544132435
oct4010754167176471
9615436536717137
10141353310551353
114104866980773a
1213a2b27584aa21
1360b47383b2684
1426c9772b2b9c5
151151dcd7408bd
hex808f61dcfd39

141353310551353 has 4 divisors (see below), whose sum is σ = 141446860063488. Its totient is φ = 141259761039220.

The previous prime is 141353310551303. The next prime is 141353310551359. The reversal of 141353310551353 is 353155013353141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141353310551353 - 29 = 141353310550841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141353310551359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46774753801 + ... + 46774756822.

It is an arithmetic number, because the mean of its divisors is an integer number (35361715015872).

Almost surely, 2141353310551353 is an apocalyptic number.

It is an amenable number.

141353310551353 is a deficient number, since it is larger than the sum of its proper divisors (93549512135).

141353310551353 is an equidigital number, since it uses as much as digits as its factorization.

141353310551353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93549512134.

The product of its (nonzero) digits is 607500, while the sum is 43.

The spelling of 141353310551353 in words is "one hundred forty-one trillion, three hundred fifty-three billion, three hundred ten million, five hundred fifty-one thousand, three hundred fifty-three".

Divisors: 1 1511 93549510623 141353310551353