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141355246345 = 528271049269
BaseRepresentation
bin1000001110100101101…
…1011110001100001001
3111111212021211112020021
42003221123132030021
54303443420340340
6144534313300441
713132625524555
oct2035133361411
9444767745207
10141355246345
1154a48395845
122348b704721
13104395a1301
146bad610865
153a24bc5e4a
hex20e96de309

141355246345 has 4 divisors (see below), whose sum is σ = 169626295620. Its totient is φ = 113084197072.

The previous prime is 141355246343. The next prime is 141355246363. The reversal of 141355246345 is 543642553141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 543642553141 = 4357124774513.

It can be written as a sum of positive squares in 2 ways, for example, as 89327461129 + 52027785216 = 298877^2 + 228096^2 .

It is a cyclic number.

It is not a de Polignac number, because 141355246345 - 21 = 141355246343 is a prime.

It is not an unprimeable number, because it can be changed into a prime (141355246343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14135524630 + ... + 14135524639.

It is an arithmetic number, because the mean of its divisors is an integer number (42406573905).

Almost surely, 2141355246345 is an apocalyptic number.

It is an amenable number.

141355246345 is a deficient number, since it is larger than the sum of its proper divisors (28271049275).

141355246345 is an equidigital number, since it uses as much as digits as its factorization.

141355246345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28271049274.

The product of its digits is 864000, while the sum is 43.

Adding to 141355246345 its reverse (543642553141), we get a palindrome (684997799486).

The spelling of 141355246345 in words is "one hundred forty-one billion, three hundred fifty-five million, two hundred forty-six thousand, three hundred forty-five".

Divisors: 1 5 28271049269 141355246345