1414054055121 has 4 divisors (see below), whose sum is σ = 1885405406832. Its totient is φ = 942702703412.

The previous prime is 1414054055119. The next prime is 1414054055189. The reversal of 1414054055121 is 1215504504141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1414054055121 - 2¹ = 1414054055119 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1414054055021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235675675851 + ... + 235675675856.

It is an arithmetic number, because the mean of its divisors is an integer number (471351351708).

Almost surely, 2^{1414054055121} is an apocalyptic number.

It is an amenable number.

1414054055121 is a deficient number, since it is larger than the sum of its proper divisors (471351351711).

1414054055121 is an equidigital number, since it uses as much as digits as its factorization.

1414054055121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 471351351710.

The product of its (nonzero) digits is 16000, while the sum is 33.

Adding to 1414054055121 its reverse (1215504504141), we get a palindrome (2629558559262).

The spelling of 1414054055121 in words is "one trillion, four hundred fourteen billion, fifty-four million, fifty-five thousand, one hundred twenty-one".