Search a number
-
+
14141020032003 = 34713673344001
BaseRepresentation
bin1100110111000111011001…
…1110011100110000000011
31212001212102222222211100210
43031301312132130300003
53323141302112011003
650024143411445203
72656440442012104
oct315616636346003
955055388884323
1014141020032003
11456219a174987
12170475abb6803
137b7652c47c77
1436c6013403ab
15197c9145b503
hexcdc7679cc03

14141020032003 has 4 divisors (see below), whose sum is σ = 18854693376008. Its totient is φ = 9427346688000.

The previous prime is 14141020031989. The next prime is 14141020032019. The reversal of 14141020032003 is 30023002014141.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14141020032003 - 24 = 14141020031987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14141025032003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2356836671998 + ... + 2356836672003.

It is an arithmetic number, because the mean of its divisors is an integer number (4713673344002).

Almost surely, 214141020032003 is an apocalyptic number.

14141020032003 is a deficient number, since it is larger than the sum of its proper divisors (4713673344005).

14141020032003 is an equidigital number, since it uses as much as digits as its factorization.

14141020032003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4713673344004.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14141020032003 its reverse (30023002014141), we get a palindrome (44164022046144).

The spelling of 14141020032003 in words is "fourteen trillion, one hundred forty-one billion, twenty million, thirty-two thousand, three".

Divisors: 1 3 4713673344001 14141020032003