Base | Representation |
---|---|
bin | 1100110111000111110111… |
… | …1000101000011111100001 |
3 | 1212001212202122220010212121 |
4 | 3031301331320220133201 |
5 | 3323142030422230403 |
6 | 50024204012024241 |
7 | 2656443511411336 |
oct | 315617570503741 |
9 | 55055678803777 |
10 | 14141144336353 |
11 | 4562253356651 |
12 | 1704794762081 |
13 | 7b767291b138 |
14 | 36c613a5a98d |
15 | 197c9c3123bd |
hex | cdc7de287e1 |
14141144336353 has 4 divisors (see below), whose sum is σ = 14145032474260. Its totient is φ = 14137256198448.
The previous prime is 14141144336351. The next prime is 14141144336387. The reversal of 14141144336353 is 35363344114141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 450049114449 + 13691095221904 = 670857^2 + 3700148^2 .
It is a cyclic number.
It is not a de Polignac number, because 14141144336353 - 21 = 14141144336351 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14141144336351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1944063498 + ... + 1944070771.
It is an arithmetic number, because the mean of its divisors is an integer number (3536258118565).
Almost surely, 214141144336353 is an apocalyptic number.
It is an amenable number.
14141144336353 is a deficient number, since it is larger than the sum of its proper divisors (3888137907).
14141144336353 is an equidigital number, since it uses as much as digits as its factorization.
14141144336353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3888137906.
The product of its digits is 622080, while the sum is 43.
The spelling of 14141144336353 in words is "fourteen trillion, one hundred forty-one billion, one hundred forty-four million, three hundred thirty-six thousand, three hundred fifty-three".
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