141412103113 has 4 divisors (see below), whose sum is σ = 143808918480. Its totient is φ = 139015287748.

The previous prime is 141412103039. The next prime is 141412103143. The reversal of 141412103113 is 311301214141.

141412103113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311301214141 = 8821 ⋅35290921.

It is a cyclic number.

It is not a de Polignac number, because 141412103113 - 2¹⁷ = 141411972041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141412103143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1198407595 + ... + 1198407712.

It is an arithmetic number, because the mean of its divisors is an integer number (35952229620).

Almost surely, 2^141412103113 is an apocalyptic number.

It is an amenable number.

141412103113 is a deficient number, since it is larger than the sum of its proper divisors (2396815367).

141412103113 is an equidigital number, since it uses as much as digits as its factorization.

141412103113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2396815366.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 141412103113 its reverse (311301214141), we get a palindrome (452713317254).

The spelling of 141412103113 in words is "one hundred forty-one billion, four hundred twelve million, one hundred three thousand, one hundred thirteen".