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141420031331 = 282461500671
BaseRepresentation
bin1000001110110101001…
…0100110110101100011
3111112000210201221112012
42003231102212311203
54304112012000311
6144544550023135
713134343301225
oct2035522466543
9445023657465
10141420031331
1154a80a14757
12234a9347aab
1310449b35217
146bb8076415
153a2a72178b
hex20ed4a6d63

141420031331 has 4 divisors (see below), whose sum is σ = 141420814464. Its totient is φ = 141419248200.

The previous prime is 141420031327. The next prime is 141420031351. The reversal of 141420031331 is 133130024141.

141420031331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 141420031331 - 22 = 141420031327 is a prime.

It is a super-3 number, since 3×1414200313313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141420031297 and 141420031306.

It is not an unprimeable number, because it can be changed into a prime (141420031301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32126 + ... + 532796.

It is an arithmetic number, because the mean of its divisors is an integer number (35355203616).

Almost surely, 2141420031331 is an apocalyptic number.

141420031331 is a deficient number, since it is larger than the sum of its proper divisors (783133).

141420031331 is an equidigital number, since it uses as much as digits as its factorization.

141420031331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 783132.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 141420031331 its reverse (133130024141), we get a palindrome (274550055472).

The spelling of 141420031331 in words is "one hundred forty-one billion, four hundred twenty million, thirty-one thousand, three hundred thirty-one".

Divisors: 1 282461 500671 141420031331