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14142020331 = 34714006777
BaseRepresentation
bin11010010101110111…
…00001101011101011
31100111120201001211210
431022323201223223
5212430324122311
610255144324203
71010311121655
oct151273415353
940446631753
1014142020331
115aa789020a
1228a8173663
131444b7598a
149822c56d5
1557b8383a6
hex34aee1aeb

14142020331 has 4 divisors (see below), whose sum is σ = 18856027112. Its totient is φ = 9428013552.

The previous prime is 14142020279. The next prime is 14142020341. The reversal of 14142020331 is 13302024141.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14142020331 - 27 = 14142020203 is a prime.

It is a super-2 number, since 2×141420203312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14142020298 and 14142020307.

It is not an unprimeable number, because it can be changed into a prime (14142020341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2357003386 + ... + 2357003391.

It is an arithmetic number, because the mean of its divisors is an integer number (4714006778).

Almost surely, 214142020331 is an apocalyptic number.

14142020331 is a deficient number, since it is larger than the sum of its proper divisors (4714006781).

14142020331 is an equidigital number, since it uses as much as digits as its factorization.

14142020331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4714006780.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14142020331 its reverse (13302024141), we get a palindrome (27444044472).

The spelling of 14142020331 in words is "fourteen billion, one hundred forty-two million, twenty thousand, three hundred thirty-one".

Divisors: 1 3 4714006777 14142020331