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1414240003 = 11128567273
BaseRepresentation
bin101010001001011…
…1001011100000011
310122120010211120101
41110102321130003
510344021140003
6352200023231
750021561461
oct12422713403
93576124511
101414240003
116663354a0
12335761b17
13196cc6207
14d5b7b831
158425911d
hex544b9703

1414240003 has 4 divisors (see below), whose sum is σ = 1542807288. Its totient is φ = 1285672720.

The previous prime is 1414239991. The next prime is 1414240007. The reversal of 1414240003 is 3000424141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1414240003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1414240007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64283626 + ... + 64283647.

It is an arithmetic number, because the mean of its divisors is an integer number (385701822).

Almost surely, 21414240003 is an apocalyptic number.

1414240003 is a deficient number, since it is larger than the sum of its proper divisors (128567285).

1414240003 is a wasteful number, since it uses less digits than its factorization.

1414240003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 128567284.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 1414240003 is about 37606.3824769147. The cubic root of 1414240003 is about 1122.4690435789.

Adding to 1414240003 its reverse (3000424141), we get a palindrome (4414664144).

It can be divided in two parts, 14142 and 40003, that added together give a palindrome (54145).

The spelling of 1414240003 in words is "one billion, four hundred fourteen million, two hundred forty thousand, three".

Divisors: 1 11 128567273 1414240003