Base | Representation |
---|---|
bin | 1100110111011000001111… |
… | …1100101001111101110011 |
3 | 1212002022010002000220010021 |
4 | 3031312003330221331303 |
5 | 3323230032000142210 |
6 | 50030212152144311 |
7 | 2656660456542466 |
oct | 315660374517563 |
9 | 55068102026107 |
10 | 14145541021555 |
11 | 45640aa151289 |
12 | 1705601098097 |
13 | 7b7bc3790408 |
14 | 36c90d9512dd |
15 | 197e582e3bda |
hex | cdd83f29f73 |
14145541021555 has 4 divisors (see below), whose sum is σ = 16974649225872. Its totient is φ = 11316432817240.
The previous prime is 14145541021553. The next prime is 14145541021631. The reversal of 14145541021555 is 55512014554141.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14145541021555 - 21 = 14145541021553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14145541021553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1414554102151 + ... + 1414554102160.
It is an arithmetic number, because the mean of its divisors is an integer number (4243662306468).
Almost surely, 214145541021555 is an apocalyptic number.
14145541021555 is a deficient number, since it is larger than the sum of its proper divisors (2829108204317).
14145541021555 is an equidigital number, since it uses as much as digits as its factorization.
14145541021555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2829108204316.
The product of its (nonzero) digits is 400000, while the sum is 43.
Adding to 14145541021555 its reverse (55512014554141), we get a palindrome (69657555575696).
The spelling of 14145541021555 in words is "fourteen trillion, one hundred forty-five billion, five hundred forty-one million, twenty-one thousand, five hundred fifty-five".
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