Base | Representation |
---|---|
bin | 11010010110010111… |
… | …11011100000110001 |
3 | 1100111212210112110211 |
4 | 31023023323200301 |
5 | 212432424223213 |
6 | 10255420424121 |
7 | 1010362511500 |
oct | 151313734061 |
9 | 40455715424 |
10 | 14146320433 |
11 | 5aaa257a13 |
12 | 28a96a8041 |
13 | 1445a2000b |
14 | 982ac4837 |
15 | 57bdd753d |
hex | 34b2fb831 |
14146320433 has 12 divisors (see below), whose sum is σ = 16457875392. Its totient is φ = 12123979560.
The previous prime is 14146320431. The next prime is 14146320443. The reversal of 14146320433 is 33402364141.
It is not a de Polignac number, because 14146320433 - 21 = 14146320431 is a prime.
It is a super-2 number, since 2×141463204332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14146320395 and 14146320404.
It is not an unprimeable number, because it can be changed into a prime (14146320431) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 726916 + ... + 746122.
It is an arithmetic number, because the mean of its divisors is an integer number (1371489616).
Almost surely, 214146320433 is an apocalyptic number.
It is an amenable number.
14146320433 is a deficient number, since it is larger than the sum of its proper divisors (2311554959).
14146320433 is a wasteful number, since it uses less digits than its factorization.
14146320433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34252 (or 34245 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 14146320433 its reverse (33402364141), we get a palindrome (47548684574).
The spelling of 14146320433 in words is "fourteen billion, one hundred forty-six million, three hundred twenty thousand, four hundred thirty-three".
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