Base | Representation |
---|---|
bin | 10100100110001110011… |
… | …001010100001000011011 |
3 | 12000022110222100200020122 |
4 | 110212032121110020123 |
5 | 141142301402203430 |
6 | 3002124022343455 |
7 | 204155520016055 |
oct | 24461631241033 |
9 | 5008428320218 |
10 | 1415433241115 |
11 | 4a6311189813 |
12 | 1aa3a188ab8b |
13 | a36231327ca |
14 | 4c7161a88d5 |
15 | 26c43001ee5 |
hex | 1498e65421b |
1415433241115 has 4 divisors (see below), whose sum is σ = 1698519889344. Its totient is φ = 1132346592888.
The previous prime is 1415433241109. The next prime is 1415433241121. The reversal of 1415433241115 is 5111423345141.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (1415433241109) and next prime (1415433241121).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1415433241115 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141543324107 + ... + 141543324116.
It is an arithmetic number, because the mean of its divisors is an integer number (424629972336).
Almost surely, 21415433241115 is an apocalyptic number.
1415433241115 is a deficient number, since it is larger than the sum of its proper divisors (283086648229).
1415433241115 is an equidigital number, since it uses as much as digits as its factorization.
1415433241115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 283086648228.
The product of its digits is 28800, while the sum is 35.
Adding to 1415433241115 its reverse (5111423345141), we get a palindrome (6526856586256).
The spelling of 1415433241115 in words is "one trillion, four hundred fifteen billion, four hundred thirty-three million, two hundred forty-one thousand, one hundred fifteen".
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