Base | Representation |
---|---|
bin | 11010010111100111… |
… | …11101100001000011 |
3 | 1100112121112200111101 |
4 | 31023303331201003 |
5 | 212443121030103 |
6 | 10300433355231 |
7 | 1010550636244 |
oct | 151363754103 |
9 | 40477480441 |
10 | 14156814403 |
11 | 6005175216 |
12 | 28b1108b17 |
13 | 1447c55674 |
14 | 984256ccb |
15 | 57ccaba1d |
hex | 34bcfd843 |
14156814403 has 4 divisors (see below), whose sum is σ = 14158256728. Its totient is φ = 14155372080.
The previous prime is 14156814391. The next prime is 14156814467. The reversal of 14156814403 is 30441865141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30441865141 = 6563 ⋅4638407.
It is a cyclic number.
It is not a de Polignac number, because 14156814403 - 213 = 14156806211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14156814703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 706338 + ... + 726103.
It is an arithmetic number, because the mean of its divisors is an integer number (3539564182).
Almost surely, 214156814403 is an apocalyptic number.
14156814403 is a deficient number, since it is larger than the sum of its proper divisors (1442325).
14156814403 is an equidigital number, since it uses as much as digits as its factorization.
14156814403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1442324.
The product of its (nonzero) digits is 46080, while the sum is 37.
The spelling of 14156814403 in words is "fourteen billion, one hundred fifty-six million, eight hundred fourteen thousand, four hundred three".
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