Base | Representation |
---|---|
bin | 11010011000010000… |
… | …01010100001011011 |
3 | 1100112222111202110011 |
4 | 31030020022201123 |
5 | 213001000014210 |
6 | 10301143102351 |
7 | 1010643645025 |
oct | 151410124133 |
9 | 40488452404 |
10 | 14162110555 |
11 | 60081622aa |
12 | 28b2a419b7 |
13 | 144908b198 |
14 | 984c35015 |
15 | 57d4a5d8a |
hex | 34c20a85b |
14162110555 has 4 divisors (see below), whose sum is σ = 16994532672. Its totient is φ = 11329688440.
The previous prime is 14162110553. The next prime is 14162110577. The reversal of 14162110555 is 55501126141.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14162110555 - 21 = 14162110553 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14162110553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1416211051 + ... + 1416211060.
It is an arithmetic number, because the mean of its divisors is an integer number (4248633168).
Almost surely, 214162110555 is an apocalyptic number.
14162110555 is a deficient number, since it is larger than the sum of its proper divisors (2832422117).
14162110555 is an equidigital number, since it uses as much as digits as its factorization.
14162110555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2832422116.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 14162110555 its reverse (55501126141), we get a palindrome (69663236696).
The spelling of 14162110555 in words is "fourteen billion, one hundred sixty-two million, one hundred ten thousand, five hundred fifty-five".
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