Base | Representation |
---|---|
bin | 11010011011001011… |
… | …01010010011100011 |
3 | 1100121200121222021020 |
4 | 31031211222103203 |
5 | 213023233321011 |
6 | 10303420300523 |
7 | 1011362165355 |
oct | 151545522343 |
9 | 40550558236 |
10 | 14186620131 |
11 | 601aa82752 |
12 | 28bb0a1743 |
13 | 14511900a8 |
14 | 9881b50d5 |
15 | 5806e8006 |
hex | 34d96a4e3 |
14186620131 has 4 divisors (see below), whose sum is σ = 18915493512. Its totient is φ = 9457746752.
The previous prime is 14186620103. The next prime is 14186620141. The reversal of 14186620131 is 13102668141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14186620131 - 213 = 14186611939 is a prime.
It is a super-2 number, since 2×141866201312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14186620092 and 14186620101.
It is not an unprimeable number, because it can be changed into a prime (14186620141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2364436686 + ... + 2364436691.
It is an arithmetic number, because the mean of its divisors is an integer number (4728873378).
Almost surely, 214186620131 is an apocalyptic number.
14186620131 is a deficient number, since it is larger than the sum of its proper divisors (4728873381).
14186620131 is an equidigital number, since it uses as much as digits as its factorization.
14186620131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4728873380.
The product of its (nonzero) digits is 6912, while the sum is 33.
The spelling of 14186620131 in words is "fourteen billion, one hundred eighty-six million, six hundred twenty thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •