Base | Representation |
---|---|
bin | 10000111011010… |
… | …10111001111011 |
3 | 100220012010101220 |
4 | 20131222321323 |
5 | 242322330033 |
6 | 22031243123 |
7 | 3342641316 |
oct | 1035527173 |
9 | 326163356 |
10 | 141995643 |
11 | 73175479 |
12 | 3b6794a3 |
13 | 235587ba |
14 | 14c0397d |
15 | c6ecbb3 |
hex | 876ae7b |
141995643 has 4 divisors (see below), whose sum is σ = 189327528. Its totient is φ = 94663760.
The previous prime is 141995641. The next prime is 141995647. The reversal of 141995643 is 346599141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141995643 - 21 = 141995641 is a prime.
It is a super-3 number, since 3×1419956433 (a number of 25 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 141995595 and 141995604.
It is not an unprimeable number, because it can be changed into a prime (141995641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23665938 + ... + 23665943.
It is an arithmetic number, because the mean of its divisors is an integer number (47331882).
Almost surely, 2141995643 is an apocalyptic number.
141995643 is a deficient number, since it is larger than the sum of its proper divisors (47331885).
141995643 is an equidigital number, since it uses as much as digits as its factorization.
141995643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47331884.
The product of its digits is 116640, while the sum is 42.
The square root of 141995643 is about 11916.1924707517. The cubic root of 141995643 is about 521.7050086764.
The spelling of 141995643 in words is "one hundred forty-one million, nine hundred ninety-five thousand, six hundred forty-three".
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