Base | Representation |
---|---|
bin | 1000010001000000100… |
… | …0010001000011100011 |
3 | 111120112112120012200111 |
4 | 2010100020101003203 |
5 | 4311311124220420 |
6 | 145122545432151 |
7 | 13155001350241 |
oct | 2042010210343 |
9 | 446475505614 |
10 | 142004523235 |
11 | 55250940113 |
12 | 2363103b657 |
13 | 10510c61113 |
14 | 6c31943791 |
15 | 3a61bc945a |
hex | 21102110e3 |
142004523235 has 4 divisors (see below), whose sum is σ = 170405427888. Its totient is φ = 113603618584.
The previous prime is 142004523119. The next prime is 142004523247. The reversal of 142004523235 is 532325400241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142004523235 - 213 = 142004515043 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142004523197 and 142004523206.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14200452319 + ... + 14200452328.
It is an arithmetic number, because the mean of its divisors is an integer number (42601356972).
Almost surely, 2142004523235 is an apocalyptic number.
142004523235 is a deficient number, since it is larger than the sum of its proper divisors (28400904653).
142004523235 is an equidigital number, since it uses as much as digits as its factorization.
142004523235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28400904652.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 142004523235 its reverse (532325400241), we get a palindrome (674329923476).
The spelling of 142004523235 in words is "one hundred forty-two billion, four million, five hundred twenty-three thousand, two hundred thirty-five".
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