1420115441 has 4 divisors (see below), whose sum is σ = 1443396084. Its totient is φ = 1396834800.

The previous prime is 1420115407. The next prime is 1420115453. The reversal of 1420115441 is 1445110241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1445110241 = 163 ⋅8865707.

It can be written as a sum of positive squares in 2 ways, for example, as 85747600 + 1334367841 = 9260^2 + 36529^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1420115441 is a prime.

It is a super-3 number, since 3×1420115441³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1420115491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11640230 + ... + 11640351.

It is an arithmetic number, because the mean of its divisors is an integer number (360849021).

Almost surely, 2^1420115441 is an apocalyptic number.

It is an amenable number.

1420115441 is a deficient number, since it is larger than the sum of its proper divisors (23280643).

1420115441 is an equidigital number, since it uses as much as digits as its factorization.

1420115441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23280642.

The product of its (nonzero) digits is 640, while the sum is 23.

The square root of 1420115441 is about 37684.4190747317. The cubic root of 1420115441 is about 1124.0213226221.

Adding to 1420115441 its reverse (1445110241), we get a palindrome (2865225682).

The spelling of 1420115441 in words is "one billion, four hundred twenty million, one hundred fifteen thousand, four hundred forty-one".