1420130311321 has 4 divisors (see below), whose sum is σ = 1420136210944. Its totient is φ = 1420124411700.

The previous prime is 1420130311309. The next prime is 1420130311351. The reversal of 1420130311321 is 1231130310241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1420130311321 is a prime.

It is a super-2 number, since 2×1420130311321² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1420130311292 and 1420130311301.

It is not an unprimeable number, because it can be changed into a prime (1420130311351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2572665 + ... + 3075526.

It is an arithmetic number, because the mean of its divisors is an integer number (355034052736).

Almost surely, 2^{1420130311321} is an apocalyptic number.

It is an amenable number.

1420130311321 is a deficient number, since it is larger than the sum of its proper divisors (5899623).

1420130311321 is an equidigital number, since it uses as much as digits as its factorization.

1420130311321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5899622.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1420130311321 its reverse (1231130310241), we get a palindrome (2651260621562).

The spelling of 1420130311321 in words is "one trillion, four hundred twenty billion, one hundred thirty million, three hundred eleven thousand, three hundred twenty-one".