142013110004033 has 4 divisors (see below), whose sum is σ = 142232604765120. Its totient is φ = 141793615242948.

The previous prime is 142013110004011. The next prime is 142013110004053. The reversal of 142013110004033 is 330400011310241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142013110004033 - 2¹⁴ = 142013109987649 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142013110004053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109747379573 + ... + 109747380866.

It is an arithmetic number, because the mean of its divisors is an integer number (35558151191280).

Almost surely, 2^{142013110004033} is an apocalyptic number.

It is an amenable number.

142013110004033 is a deficient number, since it is larger than the sum of its proper divisors (219494761087).

142013110004033 is an equidigital number, since it uses as much as digits as its factorization.

142013110004033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 219494761086.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 142013110004033 its reverse (330400011310241), we get a palindrome (472413121314274).

The spelling of 142013110004033 in words is "one hundred forty-two trillion, thirteen billion, one hundred ten million, four thousand, thirty-three".