Base | Representation |
---|---|
bin | 1100111010101000100000… |
… | …0101111011001101100001 |
3 | 1212021122102010111010001220 |
4 | 3032222020011323031201 |
5 | 3330134024423311301 |
6 | 50112015343245253 |
7 | 2664010022633532 |
oct | 316521005731541 |
9 | 55248363433056 |
10 | 14201445135201 |
11 | 45858876032a5 |
12 | 17144032a9829 |
13 | 7c02627958bc |
14 | 3714d4450689 |
15 | 19962b180936 |
hex | cea8817b361 |
14201445135201 has 4 divisors (see below), whose sum is σ = 18935260180272. Its totient is φ = 9467630090132.
The previous prime is 14201445135197. The next prime is 14201445135203. The reversal of 14201445135201 is 10253154410241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14201445135201 - 22 = 14201445135197 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14201445135203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2366907522531 + ... + 2366907522536.
It is an arithmetic number, because the mean of its divisors is an integer number (4733815045068).
Almost surely, 214201445135201 is an apocalyptic number.
It is an amenable number.
14201445135201 is a deficient number, since it is larger than the sum of its proper divisors (4733815045071).
14201445135201 is an equidigital number, since it uses as much as digits as its factorization.
14201445135201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4733815045070.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 14201445135201 its reverse (10253154410241), we get a palindrome (24454599545442).
The spelling of 14201445135201 in words is "fourteen trillion, two hundred one billion, four hundred forty-five million, one hundred thirty-five thousand, two hundred one".
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