Base | Representation |
---|---|
bin | 11010011100111110… |
… | …01110111011100001 |
3 | 1100122202000201220102 |
4 | 31032133032323201 |
5 | 213041114243403 |
6 | 10305115552145 |
7 | 1011634364123 |
oct | 151637167341 |
9 | 40582021812 |
10 | 14201712353 |
11 | 6028550764 |
12 | 290415b655 |
13 | 14543456ba |
14 | 98a1c3213 |
15 | 581bc9b88 |
hex | 34e7ceee1 |
14201712353 has 4 divisors (see below), whose sum is σ = 14204324100. Its totient is φ = 14199100608.
The previous prime is 14201712299. The next prime is 14201712359. The reversal of 14201712353 is 35321710241.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35321710241 = 311 ⋅113574631.
It can be written as a sum of positive squares in 2 ways, for example, as 1158245089 + 13043467264 = 34033^2 + 114208^2 .
It is a cyclic number.
It is not a de Polignac number, because 14201712353 - 216 = 14201646817 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14201712359) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1297700 + ... + 1308597.
It is an arithmetic number, because the mean of its divisors is an integer number (3551081025).
Almost surely, 214201712353 is an apocalyptic number.
It is an amenable number.
14201712353 is a deficient number, since it is larger than the sum of its proper divisors (2611747).
14201712353 is an equidigital number, since it uses as much as digits as its factorization.
14201712353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2611746.
The product of its (nonzero) digits is 5040, while the sum is 29.
The spelling of 14201712353 in words is "fourteen billion, two hundred one million, seven hundred twelve thousand, three hundred fifty-three".
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