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1420250998217 = 4363325521659
BaseRepresentation
bin10100101010101101100…
…011100110010111001001
312000202220201211002112212
4110222231203212113021
5141232133223420332
63004242043514505
7204416100204122
oct24525543462711
95022821732485
101420250998217
114a8363731a57
121ab307228a35
13a3c102b365c
144ca51d8b049
1526e25e5a8b2
hex14aad8e65c9

1420250998217 has 4 divisors (see below), whose sum is σ = 1420576524240. Its totient is φ = 1419925472196.

The previous prime is 1420250998213. The next prime is 1420250998253. The reversal of 1420250998217 is 7128990520241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1420250998217 - 22 = 1420250998213 is a prime.

It is a super-2 number, since 2×14202509982172 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1420250998213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162756467 + ... + 162765192.

It is an arithmetic number, because the mean of its divisors is an integer number (355144131060).

Almost surely, 21420250998217 is an apocalyptic number.

It is an amenable number.

1420250998217 is a deficient number, since it is larger than the sum of its proper divisors (325526023).

1420250998217 is an equidigital number, since it uses as much as digits as its factorization.

1420250998217 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 325526022.

The product of its (nonzero) digits is 725760, while the sum is 50.

The spelling of 1420250998217 in words is "one trillion, four hundred twenty billion, two hundred fifty million, nine hundred ninety-eight thousand, two hundred seventeen".

Divisors: 1 4363 325521659 1420250998217