1420311310113 has 4 divisors (see below), whose sum is σ = 1893748413488. Its totient is φ = 946874206740.

The previous prime is 1420311310037. The next prime is 1420311310129. The reversal of 1420311310113 is 3110131130241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1420311310113 - 2⁹ = 1420311309601 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1420311310113.

It is not an unprimeable number, because it can be changed into a prime (1420311310163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236718551683 + ... + 236718551688.

It is an arithmetic number, because the mean of its divisors is an integer number (473437103372).

Almost surely, 2^{1420311310113} is an apocalyptic number.

It is an amenable number.

1420311310113 is a deficient number, since it is larger than the sum of its proper divisors (473437103375).

1420311310113 is an equidigital number, since it uses as much as digits as its factorization.

1420311310113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 473437103374.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 1420311310113 its reverse (3110131130241), we get a palindrome (4530442440354).

The spelling of 1420311310113 in words is "one trillion, four hundred twenty billion, three hundred eleven million, three hundred ten thousand, one hundred thirteen".