1420313211131 has 4 divisors (see below), whose sum is σ = 1420316547000. Its totient is φ = 1420309875264.

The previous prime is 1420313211077. The next prime is 1420313211151. The reversal of 1420313211131 is 1311123130241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1420313211131 is a prime.

It is a super-2 number, since 2×1420313211131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1420313211097 and 1420313211106.

It is not an unprimeable number, because it can be changed into a prime (1420313211151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 916406 + ... + 1918443.

It is an arithmetic number, because the mean of its divisors is an integer number (355079136750).

Almost surely, 2^{1420313211131} is an apocalyptic number.

1420313211131 is a deficient number, since it is larger than the sum of its proper divisors (3335869).

1420313211131 is an equidigital number, since it uses as much as digits as its factorization.

1420313211131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3335868.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1420313211131 its reverse (1311123130241), we get a palindrome (2731436341372).

The spelling of 1420313211131 in words is "one trillion, four hundred twenty billion, three hundred thirteen million, two hundred eleven thousand, one hundred thirty-one".