Search a number
-
+
1420320121051 = 13109255393927
BaseRepresentation
bin10100101010110001101…
…011010010000011011011
312000210002112212220020211
4110222301223102003123
5141232303422333201
63004252553231551
7204420566555326
oct24526153220333
95023075786224
101420320121051
114a8399753a67
121ab3264025b7
13a3c21705b40
144ca5b2217bd
1526e2c061651
hex14ab1ad20db

1420320121051 has 4 divisors (see below), whose sum is σ = 1529575514992. Its totient is φ = 1311064727112.

The previous prime is 1420320121019. The next prime is 1420320121111. The reversal of 1420320121051 is 1501210230241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1420320121051 - 25 = 1420320121019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1420320121351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54627696951 + ... + 54627696976.

It is an arithmetic number, because the mean of its divisors is an integer number (382393878748).

Almost surely, 21420320121051 is an apocalyptic number.

1420320121051 is a deficient number, since it is larger than the sum of its proper divisors (109255393941).

1420320121051 is a wasteful number, since it uses less digits than its factorization.

1420320121051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109255393940.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 1420320121051 its reverse (1501210230241), we get a palindrome (2921530351292).

The spelling of 1420320121051 in words is "one trillion, four hundred twenty billion, three hundred twenty million, one hundred twenty-one thousand, fifty-one".

Divisors: 1 13 109255393927 1420320121051