14203312001113 has 4 divisors (see below), whose sum is σ = 14403358649088. Its totient is φ = 14003265353140.

The previous prime is 14203312001111. The next prime is 14203312001141. The reversal of 14203312001113 is 31110021330241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14203312001113 - 2¹ = 14203312001111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14203312001111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100023323881 + ... + 100023324022.

It is an arithmetic number, because the mean of its divisors is an integer number (3600839662272).

Almost surely, 2^{14203312001113} is an apocalyptic number.

It is an amenable number.

14203312001113 is a deficient number, since it is larger than the sum of its proper divisors (200046647975).

14203312001113 is an equidigital number, since it uses as much as digits as its factorization.

14203312001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200046647974.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 14203312001113 its reverse (31110021330241), we get a palindrome (45313333331354).

The spelling of 14203312001113 in words is "fourteen trillion, two hundred three billion, three hundred twelve million, one thousand, one hundred thirteen".