Base | Representation |
---|---|
bin | 1000010001001001000… |
… | …0001000100101010001 |
3 | 111120122000120201212010 |
4 | 2010102100020211101 |
5 | 4311344233440423 |
6 | 145130301053133 |
7 | 13155613161444 |
oct | 2042220104521 |
9 | 446560521763 |
10 | 142040140113 |
11 | 55269a57653 |
12 | 23640b571a9 |
13 | 105184518b1 |
14 | 6c3657565b |
15 | 3a64db2693 |
hex | 2112408951 |
142040140113 has 8 divisors (see below), whose sum is σ = 189491436576. Its totient is φ = 94641135200.
The previous prime is 142040140111. The next prime is 142040140129. The reversal of 142040140113 is 311041040241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 142040140113 - 21 = 142040140111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 142040140113.
It is not an unprimeable number, because it can be changed into a prime (142040140111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13066548 + ... + 13077413.
It is an arithmetic number, because the mean of its divisors is an integer number (23686429572).
Almost surely, 2142040140113 is an apocalyptic number.
It is an amenable number.
142040140113 is a deficient number, since it is larger than the sum of its proper divisors (47451296463).
142040140113 is a wasteful number, since it uses less digits than its factorization.
142040140113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26145775.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 142040140113 its reverse (311041040241), we get a palindrome (453081180354).
The spelling of 142040140113 in words is "one hundred forty-two billion, forty million, one hundred forty thousand, one hundred thirteen".
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