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14204112033 = 34734704011
BaseRepresentation
bin11010011101010000…
…11000110010100001
31100122220112122122110
431032220120302201
5213042223041113
610305243225533
71011663650226
oct151650306241
940586478573
1014204112033
11602993a671
122904b182a9
1314549a5a27
1498a64994d
15582000bc3
hex34ea18ca1

14204112033 has 4 divisors (see below), whose sum is σ = 18938816048. Its totient is φ = 9469408020.

The previous prime is 14204112031. The next prime is 14204112059. The reversal of 14204112033 is 33021140241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14204112033 - 21 = 14204112031 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14204112031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2367352003 + ... + 2367352008.

It is an arithmetic number, because the mean of its divisors is an integer number (4734704012).

Almost surely, 214204112033 is an apocalyptic number.

It is an amenable number.

14204112033 is a deficient number, since it is larger than the sum of its proper divisors (4734704015).

14204112033 is an equidigital number, since it uses as much as digits as its factorization.

14204112033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4734704014.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14204112033 its reverse (33021140241), we get a palindrome (47225252274).

The spelling of 14204112033 in words is "fourteen billion, two hundred four million, one hundred twelve thousand, thirty-three".

Divisors: 1 3 4734704011 14204112033