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14204420425403 = 131092647725031
BaseRepresentation
bin1100111010110011100101…
…1011110000011010111011
31212021221002111000111221022
43032230321123300122323
53330211123112103103
650113230510133055
72664143531323145
oct316547133603273
955257074014838
1014204420425403
11458707402691a
121714ab37b118b
137c0618008050
143716d7663c95
15199752493138
hexceb396f06bb

14204420425403 has 4 divisors (see below), whose sum is σ = 15297068150448. Its totient is φ = 13111772700360.

The previous prime is 14204420425369. The next prime is 14204420425451. The reversal of 14204420425403 is 30452402440241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14204420425403 - 224 = 14204403648187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14204420425463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546323862503 + ... + 546323862528.

It is an arithmetic number, because the mean of its divisors is an integer number (3824267037612).

Almost surely, 214204420425403 is an apocalyptic number.

14204420425403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14204420425403 is a deficient number, since it is larger than the sum of its proper divisors (1092647725045).

14204420425403 is a wasteful number, since it uses less digits than its factorization.

14204420425403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1092647725044.

The product of its (nonzero) digits is 122880, while the sum is 35.

Adding to 14204420425403 its reverse (30452402440241), we get a palindrome (44656822865644).

The spelling of 14204420425403 in words is "fourteen trillion, two hundred four billion, four hundred twenty million, four hundred twenty-five thousand, four hundred three".

Divisors: 1 13 1092647725031 14204420425403